13501100113 has 2 divisors, whose sum is σ = 13501100114. Its totient is φ = 13501100112.

The previous prime is 13501100111. The next prime is 13501100143. The reversal of 13501100113 is 31100110531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13495933584 + 5166529 = 116172^2 + 2273^2 .

It is a cyclic number.

It is not a de Polignac number, because 13501100113 - 2¹ = 13501100111 is a prime.

It is a super-2 number, since 2×13501100113² (a number of 21 digits) contains 22 as substring.

Together with 13501100111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13501100111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750550056 + 6750550057.

It is an arithmetic number, because the mean of its divisors is an integer number (6750550057).

Almost surely, 2^13501100113 is an apocalyptic number.

It is an amenable number.

13501100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13501100113 is an equidigital number, since it uses as much as digits as its factorization.

13501100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45, while the sum is 16.

Adding to 13501100113 its reverse (31100110531), we get a palindrome (44601210644).

The spelling of 13501100113 in words is "thirteen billion, five hundred one million, one hundred thousand, one hundred thirteen".