13501140000 has 240 divisors, whose sum is σ = 45325016352. Its totient is φ = 3515904000.

The previous prime is 13501139989. The next prime is 13501140013. The reversal of 13501140000 is 4110531.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2577384 + ... + 2582616.

Almost surely, 2^13501140000 is an apocalyptic number.

13501140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13501140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22662508176).

13501140000 is an abundant number, since it is smaller than the sum of its proper divisors (31823876352).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13501140000 is an equidigital number, since it uses as much as digits as its factorization.

13501140000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5309 (or 5286 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 13501140000 its reverse (4110531), we get a palindrome (13505250531).

The spelling of 13501140000 in words is "thirteen billion, five hundred one million, one hundred forty thousand".