13501452341431 has 4 divisors (see below), whose sum is σ = 13502425292712. Its totient is φ = 13500479390152.

The previous prime is 13501452341411. The next prime is 13501452341441. The reversal of 13501452341431 is 13414325410531.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13501452341431 - 2¹¹ = 13501452339383 is a prime.

It is a super-3 number, since 3×13501452341431³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13501452341411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 486454825 + ... + 486482578.

It is an arithmetic number, because the mean of its divisors is an integer number (3375606323178).

Almost surely, 2^{13501452341431} is an apocalyptic number.

13501452341431 is a deficient number, since it is larger than the sum of its proper divisors (972951281).

13501452341431 is an equidigital number, since it uses as much as digits as its factorization.

13501452341431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 972951280.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 13501452341431 its reverse (13414325410531), we get a palindrome (26915777751962).

The spelling of 13501452341431 in words is "thirteen trillion, five hundred one billion, four hundred fifty-two million, three hundred forty-one thousand, four hundred thirty-one".