Base | Representation |
---|---|
bin | 11001001001100000… |
… | …01100001100101101 |
3 | 1021211221111000002010 |
4 | 30210300030030231 |
5 | 210122341431131 |
6 | 10111424151433 |
7 | 655402660104 |
oct | 144460141455 |
9 | 37757430063 |
10 | 13501514541 |
11 | 57a9286789 |
12 | 2749768579 |
13 | 1372267278 |
14 | 9211d703b |
15 | 5404b8b46 |
hex | 324c0c32d |
13501514541 has 4 divisors (see below), whose sum is σ = 18002019392. Its totient is φ = 9001009692.
The previous prime is 13501514527. The next prime is 13501514557. The reversal of 13501514541 is 14541510531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13501514541 - 230 = 12427772717 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13501514499 and 13501514508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13501514501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2250252421 + ... + 2250252426.
It is an arithmetic number, because the mean of its divisors is an integer number (4500504848).
Almost surely, 213501514541 is an apocalyptic number.
It is an amenable number.
13501514541 is a deficient number, since it is larger than the sum of its proper divisors (4500504851).
13501514541 is an equidigital number, since it uses as much as digits as its factorization.
13501514541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4500504850.
The product of its (nonzero) digits is 6000, while the sum is 30.
The spelling of 13501514541 in words is "thirteen billion, five hundred one million, five hundred fourteen thousand, five hundred forty-one".
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