13502013405451 has 4 divisors (see below), whose sum is σ = 13502020755400. Its totient is φ = 13502006055504.

The previous prime is 13502013405427. The next prime is 13502013405467. The reversal of 13502013405451 is 15450431020531.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13502013405451 - 2²⁷ = 13501879187723 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13502013405851) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1749760 + ... + 5483218.

It is an arithmetic number, because the mean of its divisors is an integer number (3375505188850).

Almost surely, 2^{13502013405451} is an apocalyptic number.

13502013405451 is a deficient number, since it is larger than the sum of its proper divisors (7349949).

13502013405451 is an equidigital number, since it uses as much as digits as its factorization.

13502013405451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7349948.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 13502013405451 its reverse (15450431020531), we get a palindrome (28952444425982).

The spelling of 13502013405451 in words is "thirteen trillion, five hundred two billion, thirteen million, four hundred five thousand, four hundred fifty-one".