Base | Representation |
---|---|
bin | 1100010001111010111010… |
… | …1101100111101010011011 |
3 | 1202210210001112021212010002 |
4 | 3010132232231213222123 |
5 | 3232204110412441401 |
6 | 44414423410043215 |
7 | 2562326323215665 |
oct | 304365655475233 |
9 | 52723045255102 |
10 | 13502013405851 |
11 | 4336198630873 |
12 | 1620944b7950b |
13 | 76c307c953a9 |
14 | 3497027d3535 |
15 | 186341e29a6b |
hex | c47aeb67a9b |
13502013405851 has 2 divisors, whose sum is σ = 13502013405852. Its totient is φ = 13502013405850.
The previous prime is 13502013405779. The next prime is 13502013405857. The reversal of 13502013405851 is 15850431020531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13502013405851 is a prime.
It is not a weakly prime, because it can be changed into another prime (13502013405857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751006702925 + 6751006702926.
It is an arithmetic number, because the mean of its divisors is an integer number (6751006702926).
Almost surely, 213502013405851 is an apocalyptic number.
13502013405851 is a deficient number, since it is larger than the sum of its proper divisors (1).
13502013405851 is an equidigital number, since it uses as much as digits as its factorization.
13502013405851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 38.
The spelling of 13502013405851 in words is "thirteen trillion, five hundred two billion, thirteen million, four hundred five thousand, eight hundred fifty-one".
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