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13502013405539 is a prime number
BaseRepresentation
bin1100010001111010111010…
…1101100111100101100011
31202210210001112021211200112
43010132232231213211203
53232204110412434124
644414423410041535
72562326323215041
oct304365655474543
952723045254615
1013502013405539
11433619863060a
121620944b792ab
1376c307c951c9
143497027d3391
15186341e2990e
hexc47aeb67963

13502013405539 has 2 divisors, whose sum is σ = 13502013405540. Its totient is φ = 13502013405538.

The previous prime is 13502013405479. The next prime is 13502013405563. The reversal of 13502013405539 is 93550431020531.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13502013405539 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13502013405496 and 13502013405505.

It is not a weakly prime, because it can be changed into another prime (13502013405589) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751006702769 + 6751006702770.

It is an arithmetic number, because the mean of its divisors is an integer number (6751006702770).

Almost surely, 213502013405539 is an apocalyptic number.

13502013405539 is a deficient number, since it is larger than the sum of its proper divisors (1).

13502013405539 is an equidigital number, since it uses as much as digits as its factorization.

13502013405539 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 41.

The spelling of 13502013405539 in words is "thirteen trillion, five hundred two billion, thirteen million, four hundred five thousand, five hundred thirty-nine".