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13502304013339 is a prime number
BaseRepresentation
bin1100010001111100000000…
…0010001100110000011011
31202210210210210010020122101
43010133000002030300123
53232210204311411324
644414512310504231
72562336452306101
oct304370002146033
952723723106571
1013502304013339
11433632767a549
121620a06365077
1376c353254c9b
1434972d23dc71
1518635c6d0944
hexc47c008cc1b

13502304013339 has 2 divisors, whose sum is σ = 13502304013340. Its totient is φ = 13502304013338.

The previous prime is 13502304013307. The next prime is 13502304013409. The reversal of 13502304013339 is 93331040320531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13502304013339 - 25 = 13502304013307 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13502304013298 and 13502304013307.

It is not a weakly prime, because it can be changed into another prime (13502304013739) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751152006669 + 6751152006670.

It is an arithmetic number, because the mean of its divisors is an integer number (6751152006670).

Almost surely, 213502304013339 is an apocalyptic number.

13502304013339 is a deficient number, since it is larger than the sum of its proper divisors (1).

13502304013339 is an equidigital number, since it uses as much as digits as its factorization.

13502304013339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 87480, while the sum is 37.

The spelling of 13502304013339 in words is "thirteen trillion, five hundred two billion, three hundred four million, thirteen thousand, three hundred thirty-nine".