Search a number
-
+
135023053440 = 27351129892477
BaseRepresentation
bin111110111000000000…
…0000100101010000000
3110220111222200210120010
41331300000010222000
54203011400202230
6142010112344520
712516666006012
oct1756000045200
9426458623503
10135023053440
1152298aa2570
1222202b45140
13c96a7455c2
14676c64c1b2
1537a3d209b0
hex1f70004a80

135023053440 has 512 divisors, whose sum is σ = 491357664000. Its totient is φ = 31236423680.

The previous prime is 135023053427. The next prime is 135023053441. The reversal of 135023053440 is 44350320531.

135023053440 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1350230534402 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 135023053398 and 135023053407.

It is not an unprimeable number, because it can be changed into a prime (135023053441) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 54509482 + ... + 54511958.

Almost surely, 2135023053440 is an apocalyptic number.

135023053440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135023053440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (245678832000).

135023053440 is an abundant number, since it is smaller than the sum of its proper divisors (356334610560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135023053440 is a wasteful number, since it uses less digits than its factorization.

135023053440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2628 (or 2616 counting only the distinct ones).

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 135023053440 its reverse (44350320531), we get a palindrome (179373373971).

The spelling of 135023053440 in words is "one hundred thirty-five billion, twenty-three million, fifty-three thousand, four hundred forty".