Base | Representation |
---|---|
bin | 1100010001111100000010… |
… | …1100111100110100010010 |
3 | 1202210210211120012121121212 |
4 | 3010133000230330310102 |
5 | 3232210220144021432 |
6 | 44414513351020122 |
7 | 2562336646463222 |
oct | 304370054746422 |
9 | 52723746177555 |
10 | 13502315220242 |
11 | 4336332a34452 |
12 | 1620a0a06a642 |
13 | 76c355679ca4 |
14 | 34973091a082 |
15 | 18635d6962b2 |
hex | c47c0b3cd12 |
13502315220242 has 4 divisors (see below), whose sum is σ = 20253472830366. Its totient is φ = 6751157610120.
The previous prime is 13502315220227. The next prime is 13502315220263. The reversal of 13502315220242 is 24202251320531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10280430228721 + 3221884991521 = 3206311^2 + 1794961^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13502315220199 and 13502315220208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3375578805059 + ... + 3375578805062.
Almost surely, 213502315220242 is an apocalyptic number.
13502315220242 is a deficient number, since it is larger than the sum of its proper divisors (6751157610124).
13502315220242 is an equidigital number, since it uses as much as digits as its factorization.
13502315220242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6751157610123.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 13502315220242 its reverse (24202251320531), we get a palindrome (37704566540773).
The spelling of 13502315220242 in words is "thirteen trillion, five hundred two billion, three hundred fifteen million, two hundred twenty thousand, two hundred forty-two".
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