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13502315220242 = 26751157610121
BaseRepresentation
bin1100010001111100000010…
…1100111100110100010010
31202210210211120012121121212
43010133000230330310102
53232210220144021432
644414513351020122
72562336646463222
oct304370054746422
952723746177555
1013502315220242
114336332a34452
121620a0a06a642
1376c355679ca4
1434973091a082
1518635d6962b2
hexc47c0b3cd12

13502315220242 has 4 divisors (see below), whose sum is σ = 20253472830366. Its totient is φ = 6751157610120.

The previous prime is 13502315220227. The next prime is 13502315220263. The reversal of 13502315220242 is 24202251320531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10280430228721 + 3221884991521 = 3206311^2 + 1794961^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13502315220199 and 13502315220208.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3375578805059 + ... + 3375578805062.

Almost surely, 213502315220242 is an apocalyptic number.

13502315220242 is a deficient number, since it is larger than the sum of its proper divisors (6751157610124).

13502315220242 is an equidigital number, since it uses as much as digits as its factorization.

13502315220242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6751157610123.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 13502315220242 its reverse (24202251320531), we get a palindrome (37704566540773).

The spelling of 13502315220242 in words is "thirteen trillion, five hundred two billion, three hundred fifteen million, two hundred twenty thousand, two hundred forty-two".

Divisors: 1 2 6751157610121 13502315220242