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1350256165413 = 3450085388471
BaseRepresentation
bin10011101001100001100…
…010100000001000100101
311210002020200012011201220
4103221201202200020211
5134110311034243123
62512144335410553
7166360415015151
oct23514142401045
94702220164656
101350256165413
1148070544a0a1
12199832083a59
139a436c57c1c
14494d1d1c061
15251cb01ace3
hex13a618a0225

1350256165413 has 4 divisors (see below), whose sum is σ = 1800341553888. Its totient is φ = 900170776940.

The previous prime is 1350256165399. The next prime is 1350256165451. The reversal of 1350256165413 is 3145616520531.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1350256165413 - 213 = 1350256157221 is a prime.

It is a super-4 number, since 4×13502561654134 (a number of 50 digits) contains 4444 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350256165483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225042694233 + ... + 225042694238.

It is an arithmetic number, because the mean of its divisors is an integer number (450085388472).

Almost surely, 21350256165413 is an apocalyptic number.

It is an amenable number.

1350256165413 is a deficient number, since it is larger than the sum of its proper divisors (450085388475).

1350256165413 is an equidigital number, since it uses as much as digits as its factorization.

1350256165413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450085388474.

The product of its (nonzero) digits is 324000, while the sum is 42.

The spelling of 1350256165413 in words is "one trillion, three hundred fifty billion, two hundred fifty-six million, one hundred sixty-five thousand, four hundred thirteen".

Divisors: 1 3 450085388471 1350256165413