Base | Representation |
---|---|
bin | 10011101001100100001… |
… | …011101000000111011011 |
3 | 11210002100202121121222001 |
4 | 103221210023220013123 |
5 | 134110403412003233 |
6 | 2512153001541431 |
7 | 166361463606616 |
oct | 23514413500733 |
9 | 4702322547861 |
10 | 1350300500443 |
11 | 480728480714 |
12 | 199844aa4877 |
13 | 9a4431ab97b |
14 | 494d7b7d17d |
15 | 251ced7727d |
hex | 13a642e81db |
1350300500443 has 2 divisors, whose sum is σ = 1350300500444. Its totient is φ = 1350300500442.
The previous prime is 1350300500411. The next prime is 1350300500447. The reversal of 1350300500443 is 3440050030531.
It is a strong prime.
It is an emirp because it is prime and its reverse (3440050030531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1350300500443 - 25 = 1350300500411 is a prime.
It is a super-2 number, since 2×13503005004432 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1350300500447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675150250221 + 675150250222.
It is an arithmetic number, because the mean of its divisors is an integer number (675150250222).
Almost surely, 21350300500443 is an apocalyptic number.
1350300500443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350300500443 is an equidigital number, since it uses as much as digits as its factorization.
1350300500443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 28.
Adding to 1350300500443 its reverse (3440050030531), we get a palindrome (4790350530974).
The spelling of 1350300500443 in words is "one trillion, three hundred fifty billion, three hundred million, five hundred thousand, four hundred forty-three".
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