Base | Representation |
---|---|
bin | 1100010001111111001101… |
… | …0111100010011001100111 |
3 | 1202210220000210200100102110 |
4 | 3010133303113202121213 |
5 | 3232213440300320111 |
6 | 44415133554012103 |
7 | 2562400010536500 |
oct | 304376327423147 |
9 | 52726023610373 |
10 | 13503165245031 |
11 | 4336729832680 |
12 | 1621006877033 |
13 | 76c45c7c6637 |
14 | 3497b1787ba7 |
15 | 1863ad1005a6 |
hex | c47f35e2667 |
13503165245031 has 48 divisors (see below), whose sum is σ = 24191636048640. Its totient is φ = 6602005912320.
The previous prime is 13503165245029. The next prime is 13503165245039. The reversal of 13503165245031 is 13054256130531.
It is not a de Polignac number, because 13503165245031 - 21 = 13503165245029 is a prime.
It is a super-2 number, since 2×135031652450312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13503165245039) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 245582851 + ... + 245637828.
It is an arithmetic number, because the mean of its divisors is an integer number (503992417680).
Almost surely, 213503165245031 is an apocalyptic number.
13503165245031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13503165245031 is a deficient number, since it is larger than the sum of its proper divisors (10688470803609).
13503165245031 is a wasteful number, since it uses less digits than its factorization.
13503165245031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 491220724 (or 491220717 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 39.
The spelling of 13503165245031 in words is "thirteen trillion, five hundred three billion, one hundred sixty-five million, two hundred forty-five thousand, thirty-one".
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