Search a number
-
+
1350327441217 is a prime number
BaseRepresentation
bin10011101001100101110…
…010011001011101000001
311210002102122022100202111
4103221211302121131001
5134110432311104332
62512155403215321
7166362241604266
oct23514562313501
94702378270674
101350327441217
11480741701717
12199851b17541
139a448952361
14494db59326d
15251d23e9947
hex13a65c99741

1350327441217 has 2 divisors, whose sum is σ = 1350327441218. Its totient is φ = 1350327441216.

The previous prime is 1350327441209. The next prime is 1350327441223. The reversal of 1350327441217 is 7121447230531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1258976005681 + 91351435536 = 1122041^2 + 302244^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350327441217 - 23 = 1350327441209 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1350327441217.

It is not a weakly prime, because it can be changed into another prime (1350327441257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675163720608 + 675163720609.

It is an arithmetic number, because the mean of its divisors is an integer number (675163720609).

Almost surely, 21350327441217 is an apocalyptic number.

It is an amenable number.

1350327441217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350327441217 is an equidigital number, since it uses as much as digits as its factorization.

1350327441217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 141120, while the sum is 40.

The spelling of 1350327441217 in words is "one trillion, three hundred fifty billion, three hundred twenty-seven million, four hundred forty-one thousand, two hundred seventeen".