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13503401 is a prime number
BaseRepresentation
bin110011100000…
…101110101001
3221102001011222
4303200232221
511424102101
61201231425
7222530342
oct63405651
927361158
1013503401
11769333a
124632575
132a4a3a2
141b170c9
1512bb01b
hexce0ba9

13503401 has 2 divisors, whose sum is σ = 13503402. Its totient is φ = 13503400.

The previous prime is 13503377. The next prime is 13503407. The reversal of 13503401 is 10430531.

13503401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8323225 + 5180176 = 2885^2 + 2276^2 .

It is a cyclic number.

It is not a de Polignac number, because 13503401 - 218 = 13241257 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13503401.

It is not a weakly prime, because it can be changed into another prime (13503407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751700 + 6751701.

It is an arithmetic number, because the mean of its divisors is an integer number (6751701).

Almost surely, 213503401 is an apocalyptic number.

It is an amenable number.

13503401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13503401 is an equidigital number, since it uses as much as digits as its factorization.

13503401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 13503401 is about 3674.6974025081. The cubic root of 13503401 is about 238.1301514903.

Adding to 13503401 its reverse (10430531), we get a palindrome (23933932).

The spelling of 13503401 in words is "thirteen million, five hundred three thousand, four hundred one".