Base | Representation |
---|---|
bin | 111110111000010101… |
… | …1000000111111110001 |
3 | 110220112202212201112111 |
4 | 1331300223000333301 |
5 | 4203022240420031 |
6 | 142011153525321 |
7 | 12520163462566 |
oct | 1756053007761 |
9 | 426482781474 |
10 | 135034310641 |
11 | 522a439123a |
12 | 22206873841 |
13 | c96cb87479 |
14 | 676dd3c86d |
15 | 37a4ce61b1 |
hex | 1f70ac0ff1 |
135034310641 has 2 divisors, whose sum is σ = 135034310642. Its totient is φ = 135034310640.
The previous prime is 135034310599. The next prime is 135034310647. The reversal of 135034310641 is 146013430531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110423290000 + 24611020641 = 332300^2 + 156879^2 .
It is a cyclic number.
It is not a de Polignac number, because 135034310641 - 213 = 135034302449 is a prime.
It is a super-3 number, since 3×1350343106413 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (135034310647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67517155320 + 67517155321.
It is an arithmetic number, because the mean of its divisors is an integer number (67517155321).
Almost surely, 2135034310641 is an apocalyptic number.
It is an amenable number.
135034310641 is a deficient number, since it is larger than the sum of its proper divisors (1).
135034310641 is an equidigital number, since it uses as much as digits as its factorization.
135034310641 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 31.
The spelling of 135034310641 in words is "one hundred thirty-five billion, thirty-four million, three hundred ten thousand, six hundred forty-one".
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