Base | Representation |
---|---|
bin | 111110111000100011… |
… | …0101011001100001001 |
3 | 110220120021112002122101 |
4 | 1331301012223030021 |
5 | 4203031114430403 |
6 | 142012013153401 |
7 | 12520312221646 |
oct | 1756106531411 |
9 | 426507462571 |
10 | 135041561353 |
11 | 522a8493866 |
12 | 2220918b861 |
13 | c97152582a |
14 | 6770ca8dcd |
15 | 37a577971d |
hex | 1f711ab309 |
135041561353 has 2 divisors, whose sum is σ = 135041561354. Its totient is φ = 135041561352.
The previous prime is 135041561341. The next prime is 135041561371. The reversal of 135041561353 is 353165140531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129102238864 + 5939322489 = 359308^2 + 77067^2 .
It is a cyclic number.
It is not a de Polignac number, because 135041561353 - 213 = 135041553161 is a prime.
It is not a weakly prime, because it can be changed into another prime (135041561453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67520780676 + 67520780677.
It is an arithmetic number, because the mean of its divisors is an integer number (67520780677).
Almost surely, 2135041561353 is an apocalyptic number.
It is an amenable number.
135041561353 is a deficient number, since it is larger than the sum of its proper divisors (1).
135041561353 is an equidigital number, since it uses as much as digits as its factorization.
135041561353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81000, while the sum is 37.
The spelling of 135041561353 in words is "one hundred thirty-five billion, forty-one million, five hundred sixty-one thousand, three hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •