Base | Representation |
---|---|
bin | 111110111000100101… |
… | …0011010100111100111 |
3 | 110220120100100220220200 |
4 | 1331301022122213213 |
5 | 4203031342321210 |
6 | 142012050201543 |
7 | 12520323445101 |
oct | 1756112324747 |
9 | 426510326820 |
10 | 135042542055 |
11 | 522a8aa3663 |
12 | 222095832b3 |
13 | c9717aa025 |
14 | 6771082571 |
15 | 37a58c00c0 |
hex | 1f7129a9e7 |
135042542055 has 24 divisors (see below), whose sum is σ = 238041095760. Its totient is φ = 70801964160.
The previous prime is 135042542053. The next prime is 135042542059. The reversal of 135042542055 is 550245240531.
135042542055 is a `hidden beast` number, since 1 + 350 + 4 + 254 + 2 + 0 + 55 = 666.
It is not a de Polignac number, because 135042542055 - 21 = 135042542053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135042542051) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 25429086 + ... + 25434395.
It is an arithmetic number, because the mean of its divisors is an integer number (9918378990).
Almost surely, 2135042542055 is an apocalyptic number.
135042542055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
135042542055 is a deficient number, since it is larger than the sum of its proper divisors (102998553705).
135042542055 is a wasteful number, since it uses less digits than its factorization.
135042542055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50863551 (or 50863548 counting only the distinct ones).
The product of its (nonzero) digits is 120000, while the sum is 36.
Adding to 135042542055 its reverse (550245240531), we get a palindrome (685287782586).
The spelling of 135042542055 in words is "one hundred thirty-five billion, forty-two million, five hundred forty-two thousand, fifty-five".
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