Base | Representation |
---|---|
bin | 1100010010000011010011… |
… | …0000001101010010110101 |
3 | 1202210222212020212000120121 |
4 | 3010200310300031102311 |
5 | 3232223212112344341 |
6 | 44415434502131541 |
7 | 2562436131011116 |
oct | 304406460152265 |
9 | 52728766760517 |
10 | 13504262231221 |
11 | 4337141a79633 |
12 | 1621272120bb1 |
13 | 76c5a5b605a8 |
14 | 34987734020d |
15 | 18642458d4d1 |
hex | c4834c0d4b5 |
13504262231221 has 16 divisors (see below), whose sum is σ = 13568377800960. Its totient is φ = 13440292145280.
The previous prime is 13504262231209. The next prime is 13504262231249. The reversal of 13504262231221 is 12213226240531.
It is a cyclic number.
It is not a de Polignac number, because 13504262231221 - 25 = 13504262231189 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13504262231321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1449106000 + ... + 1449115318.
It is an arithmetic number, because the mean of its divisors is an integer number (848023612560).
Almost surely, 213504262231221 is an apocalyptic number.
It is an amenable number.
13504262231221 is a deficient number, since it is larger than the sum of its proper divisors (64115569739).
13504262231221 is an equidigital number, since it uses as much as digits as its factorization.
13504262231221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16404.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 13504262231221 its reverse (12213226240531), we get a palindrome (25717488471752).
The spelling of 13504262231221 in words is "thirteen trillion, five hundred four billion, two hundred sixty-two million, two hundred thirty-one thousand, two hundred twenty-one".
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