Base | Representation |
---|---|
bin | 10011101001101100011… |
… | …111110100011010110001 |
3 | 11210002201111010112002001 |
4 | 103221230133310122301 |
5 | 134111200120331231 |
6 | 2512214504054001 |
7 | 166365106462333 |
oct | 23515437643261 |
9 | 4702644115061 |
10 | 1350440011441 |
11 | 48079a1a9364 |
12 | 199883764301 |
13 | 9a466077561 |
14 | 4950c4d7453 |
15 | 251dc233b61 |
hex | 13a6c7f46b1 |
1350440011441 has 2 divisors, whose sum is σ = 1350440011442. Its totient is φ = 1350440011440.
The previous prime is 1350440011433. The next prime is 1350440011511. The reversal of 1350440011441 is 1441100440531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 926606460816 + 423833550625 = 962604^2 + 651025^2 .
It is a cyclic number.
It is not a de Polignac number, because 1350440011441 - 23 = 1350440011433 is a prime.
It is not a weakly prime, because it can be changed into another prime (1350440011411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675220005720 + 675220005721.
It is an arithmetic number, because the mean of its divisors is an integer number (675220005721).
Almost surely, 21350440011441 is an apocalyptic number.
It is an amenable number.
1350440011441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350440011441 is an equidigital number, since it uses as much as digits as its factorization.
1350440011441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 1350440011441 its reverse (1441100440531), we get a palindrome (2791540451972).
The spelling of 1350440011441 in words is "one trillion, three hundred fifty billion, four hundred forty million, eleven thousand, four hundred forty-one".
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