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1350440011441 is a prime number
BaseRepresentation
bin10011101001101100011…
…111110100011010110001
311210002201111010112002001
4103221230133310122301
5134111200120331231
62512214504054001
7166365106462333
oct23515437643261
94702644115061
101350440011441
1148079a1a9364
12199883764301
139a466077561
144950c4d7453
15251dc233b61
hex13a6c7f46b1

1350440011441 has 2 divisors, whose sum is σ = 1350440011442. Its totient is φ = 1350440011440.

The previous prime is 1350440011433. The next prime is 1350440011511. The reversal of 1350440011441 is 1441100440531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 926606460816 + 423833550625 = 962604^2 + 651025^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350440011441 - 23 = 1350440011433 is a prime.

It is not a weakly prime, because it can be changed into another prime (1350440011411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675220005720 + 675220005721.

It is an arithmetic number, because the mean of its divisors is an integer number (675220005721).

Almost surely, 21350440011441 is an apocalyptic number.

It is an amenable number.

1350440011441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350440011441 is an equidigital number, since it uses as much as digits as its factorization.

1350440011441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 1350440011441 its reverse (1441100440531), we get a palindrome (2791540451972).

The spelling of 1350440011441 in words is "one trillion, three hundred fifty billion, four hundred forty million, eleven thousand, four hundred forty-one".