Base | Representation |
---|---|
bin | 10011101001101100100… |
… | …101100010110110010011 |
3 | 11210002201120221202220212 |
4 | 103221230211202312103 |
5 | 134111201011343324 |
6 | 2512215000154335 |
7 | 166365125313203 |
oct | 23515445426623 |
9 | 4702646852825 |
10 | 1350441512339 |
11 | 4807a0033a77 |
12 | 1998841689ab |
13 | 9a46648176a |
14 | 4950c7a8403 |
15 | 251dc42d70e |
hex | 13a6c962d93 |
1350441512339 has 2 divisors, whose sum is σ = 1350441512340. Its totient is φ = 1350441512338.
The previous prime is 1350441512309. The next prime is 1350441512363. The reversal of 1350441512339 is 9332151440531.
It is a strong prime.
It is an emirp because it is prime and its reverse (9332151440531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1350441512339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1350441512296 and 1350441512305.
It is not a weakly prime, because it can be changed into another prime (1350441512309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675220756169 + 675220756170.
It is an arithmetic number, because the mean of its divisors is an integer number (675220756170).
Almost surely, 21350441512339 is an apocalyptic number.
1350441512339 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350441512339 is an equidigital number, since it uses as much as digits as its factorization.
1350441512339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 194400, while the sum is 41.
The spelling of 1350441512339 in words is "one trillion, three hundred fifty billion, four hundred forty-one million, five hundred twelve thousand, three hundred thirty-nine".
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