Base | Representation |
---|---|
bin | 10011101001101101000… |
… | …110000101110001100011 |
3 | 11210002202012000020011102 |
4 | 103221231012011301203 |
5 | 134111210202402003 |
6 | 2512215503105015 |
7 | 166365260655644 |
oct | 23515506056143 |
9 | 4702665006142 |
10 | 1350450044003 |
11 | 4807a4930a35 |
12 | 199886ba216b |
13 | 9a46817ab98 |
14 | 4950d9896cb |
15 | 251dd066588 |
hex | 13a6d185c63 |
1350450044003 has 2 divisors, whose sum is σ = 1350450044004. Its totient is φ = 1350450044002.
The previous prime is 1350450043993. The next prime is 1350450044059. The reversal of 1350450044003 is 3004400540531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1350450044003 - 240 = 250938416227 is a prime.
It is not a weakly prime, because it can be changed into another prime (1350450044803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675225022001 + 675225022002.
It is an arithmetic number, because the mean of its divisors is an integer number (675225022002).
Almost surely, 21350450044003 is an apocalyptic number.
1350450044003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350450044003 is an equidigital number, since it uses as much as digits as its factorization.
1350450044003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 1350450044003 its reverse (3004400540531), we get a palindrome (4354850584534).
The spelling of 1350450044003 in words is "one trillion, three hundred fifty billion, four hundred fifty million, forty-four thousand, three".
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