Base | Representation |
---|---|
bin | 10011101001101101111… |
… | …101010001110001000001 |
3 | 11210002210012020020012122 |
4 | 103221231331101301001 |
5 | 134111222403323131 |
6 | 2512221141134025 |
7 | 166365524641622 |
oct | 23515575216101 |
9 | 4702705206178 |
10 | 1350464511041 |
11 | 480802012268 |
12 | 19988b9ba315 |
13 | 9a46b174a69 |
14 | 49511873a49 |
15 | 251de472d7b |
hex | 13a6df51c41 |
1350464511041 has 2 divisors, whose sum is σ = 1350464511042. Its totient is φ = 1350464511040.
The previous prime is 1350464511023. The next prime is 1350464511101. The reversal of 1350464511041 is 1401154640531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1040359200400 + 310105310641 = 1019980^2 + 556871^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1350464511041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1350464510992 and 1350464511010.
It is not a weakly prime, because it can be changed into another prime (1350464511841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675232255520 + 675232255521.
It is an arithmetic number, because the mean of its divisors is an integer number (675232255521).
Almost surely, 21350464511041 is an apocalyptic number.
It is an amenable number.
1350464511041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350464511041 is an equidigital number, since it uses as much as digits as its factorization.
1350464511041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 35.
The spelling of 1350464511041 in words is "one trillion, three hundred fifty billion, four hundred sixty-four million, five hundred eleven thousand, forty-one".
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