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135057701363353 is a prime number
BaseRepresentation
bin11110101101010110010010…
…010100000101111010011001
3122201012101112102102101020121
4132231112102110011322121
5120200241133022111403
61155124352414553241
740306411513026016
oct3655262224057231
9581171472371217
10135057701363353
113a04071652203a
1213193106b08821
135a48b6aababb2
14254cb8300270d
15109326281a3bd
hex7ad592505e99

135057701363353 has 2 divisors, whose sum is σ = 135057701363354. Its totient is φ = 135057701363352.

The previous prime is 135057701363303. The next prime is 135057701363363. The reversal of 135057701363353 is 353363107750531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102722522284944 + 32335179078409 = 10135212^2 + 5686403^2 .

It is a cyclic number.

It is not a de Polignac number, because 135057701363353 - 241 = 132858678107801 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 135057701363353.

It is not a weakly prime, because it can be changed into another prime (135057701363303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67528850681676 + 67528850681677.

It is an arithmetic number, because the mean of its divisors is an integer number (67528850681677).

Almost surely, 2135057701363353 is an apocalyptic number.

It is an amenable number.

135057701363353 is a deficient number, since it is larger than the sum of its proper divisors (1).

135057701363353 is an equidigital number, since it uses as much as digits as its factorization.

135057701363353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8930250, while the sum is 52.

The spelling of 135057701363353 in words is "one hundred thirty-five trillion, fifty-seven billion, seven hundred one million, three hundred sixty-three thousand, three hundred fifty-three".