Base | Representation |
---|---|
bin | 10011101001111000000… |
… | …100011010000100110010 |
3 | 11210010020000102220012002 |
4 | 103221320010122010302 |
5 | 134112044320332432 |
6 | 2512250041134002 |
7 | 166402654604444 |
oct | 23517004320462 |
9 | 4703200386162 |
10 | 1350634152242 |
11 | 48088984a201 |
12 | 19991878a302 |
13 | 9a49735c97b |
14 | 4952a1d2494 |
15 | 251ee2d1e62 |
hex | 13a7811a132 |
1350634152242 has 4 divisors (see below), whose sum is σ = 2025951228366. Its totient is φ = 675317076120.
The previous prime is 1350634152233. The next prime is 1350634152317. The reversal of 1350634152242 is 2422514360531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1273943373481 + 76690778761 = 1128691^2 + 276931^2 .
It is a super-2 number, since 2×13506341522422 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1350634152196 and 1350634152205.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 337658538059 + ... + 337658538062.
Almost surely, 21350634152242 is an apocalyptic number.
1350634152242 is a deficient number, since it is larger than the sum of its proper divisors (675317076124).
1350634152242 is an equidigital number, since it uses as much as digits as its factorization.
1350634152242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 675317076123.
The product of its (nonzero) digits is 172800, while the sum is 38.
The spelling of 1350634152242 in words is "one trillion, three hundred fifty billion, six hundred thirty-four million, one hundred fifty-two thousand, two hundred forty-two".
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