Base | Representation |
---|---|
bin | 111110111001010000… |
… | …0100100000100010110 |
3 | 110220121220212021002022 |
4 | 1331302200210010112 |
5 | 4203103133001032 |
6 | 142014214213142 |
7 | 12521016423023 |
oct | 1756240440426 |
9 | 426556767068 |
10 | 135065125142 |
11 | 5230a818672 |
12 | 222150541b2 |
13 | c9763860bc |
14 | 677408054a |
15 | 37a7881512 |
hex | 1f72824116 |
135065125142 has 4 divisors (see below), whose sum is σ = 202597687716. Its totient is φ = 67532562570.
The previous prime is 135065125133. The next prime is 135065125159. The reversal of 135065125142 is 241521560531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241521560531 = 3217 ⋅75076643.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33766281284 + ... + 33766281287.
It is an arithmetic number, because the mean of its divisors is an integer number (50649421929).
Almost surely, 2135065125142 is an apocalyptic number.
135065125142 is a deficient number, since it is larger than the sum of its proper divisors (67532562574).
135065125142 is an equidigital number, since it uses as much as digits as its factorization.
135065125142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67532562573.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 135065125142 its reverse (241521560531), we get a palindrome (376586685673).
The spelling of 135065125142 in words is "one hundred thirty-five billion, sixty-five million, one hundred twenty-five thousand, one hundred forty-two".
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