Base | Representation |
---|---|
bin | 11001001010001110… |
… | …00000000101100001 |
3 | 1021212100201210200111 |
4 | 30211013000011201 |
5 | 210130404303431 |
6 | 10112200251321 |
7 | 655504543453 |
oct | 144507000541 |
9 | 37770653614 |
10 | 13507494241 |
11 | 58016a038a |
12 | 274b770b41 |
13 | 137357bc57 |
14 | 921d122d3 |
15 | 540c9a7b1 |
hex | 3251c0161 |
13507494241 has 2 divisors, whose sum is σ = 13507494242. Its totient is φ = 13507494240.
The previous prime is 13507494223. The next prime is 13507494271. The reversal of 13507494241 is 14249470531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13496630625 + 10863616 = 116175^2 + 3296^2 .
It is a cyclic number.
It is not a de Polignac number, because 13507494241 - 227 = 13373276513 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13507494194 and 13507494203.
It is not a weakly prime, because it can be changed into another prime (13507494271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6753747120 + 6753747121.
It is an arithmetic number, because the mean of its divisors is an integer number (6753747121).
Almost surely, 213507494241 is an apocalyptic number.
It is an amenable number.
13507494241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13507494241 is an equidigital number, since it uses as much as digits as its factorization.
13507494241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 40.
The spelling of 13507494241 in words is "thirteen billion, five hundred seven million, four hundred ninety-four thousand, two hundred forty-one".
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