Base | Representation |
---|---|
bin | 10011101010001100010… |
… | …110001000101000111011 |
3 | 11210011002201120102012011 |
4 | 103222030112020220323 |
5 | 134113243412444424 |
6 | 2512343512430351 |
7 | 166414255310416 |
oct | 23521426105073 |
9 | 4704081512164 |
10 | 1350974343739 |
11 | 480a438850a9 |
12 | 1999b26a83b7 |
13 | 9a51c990507 |
14 | 4955d468b7d |
15 | 2521e0ce694 |
hex | 13a8c588a3b |
1350974343739 has 2 divisors, whose sum is σ = 1350974343740. Its totient is φ = 1350974343738.
The previous prime is 1350974343703. The next prime is 1350974343773. The reversal of 1350974343739 is 9373434790531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1350974343739 - 215 = 1350974310971 is a prime.
It is not a weakly prime, because it can be changed into another prime (1350974353739) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675487171869 + 675487171870.
It is an arithmetic number, because the mean of its divisors is an integer number (675487171870).
Almost surely, 21350974343739 is an apocalyptic number.
1350974343739 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350974343739 is an equidigital number, since it uses as much as digits as its factorization.
1350974343739 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25719120, while the sum is 58.
The spelling of 1350974343739 in words is "one trillion, three hundred fifty billion, nine hundred seventy-four million, three hundred forty-three thousand, seven hundred thirty-nine".
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