Base | Representation |
---|---|
bin | 10011101010010000010… |
… | …110001001000101101010 |
3 | 11210011021101211222202202 |
4 | 103222100112021011222 |
5 | 134113413103020232 |
6 | 2512354311100202 |
7 | 166416031611431 |
oct | 23522026110552 |
9 | 4704241758682 |
10 | 1351041454442 |
11 | 480a78752399 |
12 | 199a11071662 |
13 | 9a530859ba4 |
14 | 49568338118 |
15 | 25224e39162 |
hex | 13a9058916a |
1351041454442 has 4 divisors (see below), whose sum is σ = 2026562181666. Its totient is φ = 675520727220.
The previous prime is 1351041454439. The next prime is 1351041454489. The reversal of 1351041454442 is 2444541401531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1270379206321 + 80662248121 = 1127111^2 + 284011^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1351041454396 and 1351041454405.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 337760363609 + ... + 337760363612.
Almost surely, 21351041454442 is an apocalyptic number.
1351041454442 is a deficient number, since it is larger than the sum of its proper divisors (675520727224).
1351041454442 is an equidigital number, since it uses as much as digits as its factorization.
1351041454442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 675520727223.
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 1351041454442 its reverse (2444541401531), we get a palindrome (3795582855973).
The spelling of 1351041454442 in words is "one trillion, three hundred fifty-one billion, forty-one million, four hundred fifty-four thousand, four hundred forty-two".
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