Base | Representation |
---|---|
bin | 10011101010010000111… |
… | …111010001001011010001 |
3 | 11210011022011010201120012 |
4 | 103222100333101023101 |
5 | 134113423333013343 |
6 | 2512355334124305 |
7 | 166416222343133 |
oct | 23522077211321 |
9 | 4704264121505 |
10 | 1351052235473 |
11 | 480a83846336 |
12 | 199a147b0695 |
13 | 9a532b630b5 |
14 | 49569943053 |
15 | 25225d68718 |
hex | 13a90fd12d1 |
1351052235473 has 2 divisors, whose sum is σ = 1351052235474. Its totient is φ = 1351052235472.
The previous prime is 1351052235469. The next prime is 1351052235539. The reversal of 1351052235473 is 3745322501531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 838585242049 + 512466993424 = 915743^2 + 715868^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351052235473 - 22 = 1351052235469 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1351052235473.
It is not a weakly prime, because it can be changed into another prime (1351052235173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675526117736 + 675526117737.
It is an arithmetic number, because the mean of its divisors is an integer number (675526117737).
Almost surely, 21351052235473 is an apocalyptic number.
It is an amenable number.
1351052235473 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351052235473 is an equidigital number, since it uses as much as digits as its factorization.
1351052235473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378000, while the sum is 41.
The spelling of 1351052235473 in words is "one trillion, three hundred fifty-one billion, fifty-two million, two hundred thirty-five thousand, four hundred seventy-three".
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