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1351104226057 is a prime number
BaseRepresentation
bin10011101010010100000…
…101100110001100001001
311210011102202222010020101
4103222110011212030021
5134114030140213212
62512404432325401
7166420423301155
oct23522405461411
94704382863211
101351104226057
11481000126663
12199a2a0a3861
139a540867561
14495727d8065
152522a6d8157
hex13a94166309

1351104226057 has 2 divisors, whose sum is σ = 1351104226058. Its totient is φ = 1351104226056.

The previous prime is 1351104226049. The next prime is 1351104226061. The reversal of 1351104226057 is 7506224011531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1276784742601 + 74319483456 = 1129949^2 + 272616^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351104226057 - 23 = 1351104226049 is a prime.

It is not a weakly prime, because it can be changed into another prime (1351104226007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675552113028 + 675552113029.

It is an arithmetic number, because the mean of its divisors is an integer number (675552113029).

Almost surely, 21351104226057 is an apocalyptic number.

It is an amenable number.

1351104226057 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351104226057 is an equidigital number, since it uses as much as digits as its factorization.

1351104226057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 37.

Adding to 1351104226057 its reverse (7506224011531), we get a palindrome (8857328237588).

The spelling of 1351104226057 in words is "one trillion, three hundred fifty-one billion, one hundred four million, two hundred twenty-six thousand, fifty-seven".