Base | Representation |
---|---|
bin | 10011101010010100010… |
… | …010001111110110010001 |
3 | 11210011110000012121102112 |
4 | 103222110102033312101 |
5 | 134114032012324132 |
6 | 2512405031355105 |
7 | 166420463422643 |
oct | 23522422176621 |
9 | 4704400177375 |
10 | 1351107542417 |
11 | 481001a91256 |
12 | 199a2b222a95 |
13 | 9a541458bb9 |
14 | 4957301c893 |
15 | 2522ab40ab2 |
hex | 13a9448fd91 |
1351107542417 has 2 divisors, whose sum is σ = 1351107542418. Its totient is φ = 1351107542416.
The previous prime is 1351107542413. The next prime is 1351107542461. The reversal of 1351107542417 is 7142457011531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1044563717521 + 306543824896 = 1022039^2 + 553664^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351107542417 - 22 = 1351107542413 is a prime.
It is a super-2 number, since 2×13511075424172 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1351107542413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675553771208 + 675553771209.
It is an arithmetic number, because the mean of its divisors is an integer number (675553771209).
Almost surely, 21351107542417 is an apocalyptic number.
It is an amenable number.
1351107542417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351107542417 is an equidigital number, since it uses as much as digits as its factorization.
1351107542417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 117600, while the sum is 41.
The spelling of 1351107542417 in words is "one trillion, three hundred fifty-one billion, one hundred seven million, five hundred forty-two thousand, four hundred seventeen".
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