Base | Representation |
---|---|
bin | 10011101010010100100… |
… | …111000101101001001011 |
3 | 11210011110101111011120020 |
4 | 103222110213011221023 |
5 | 134114034412140033 |
6 | 2512405344431523 |
7 | 166420561025502 |
oct | 23522447055113 |
9 | 4704411434506 |
10 | 1351113005643 |
11 | 481005082915 |
12 | 199a310185a3 |
13 | 9a54261c78b |
14 | 49573a41839 |
15 | 2522b36e6b3 |
hex | 13a949c5a4b |
1351113005643 has 32 divisors (see below), whose sum is σ = 1812134373120. Its totient is φ = 895438177920.
The previous prime is 1351113005633. The next prime is 1351113005663. The reversal of 1351113005643 is 3465003111531.
It is a happy number.
It is not a de Polignac number, because 1351113005643 - 26 = 1351113005579 is a prime.
It is a super-2 number, since 2×13511130056432 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1351113005633) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 569848248 + ... + 569850618.
It is an arithmetic number, because the mean of its divisors is an integer number (56629199160).
Almost surely, 21351113005643 is an apocalyptic number.
1351113005643 is a deficient number, since it is larger than the sum of its proper divisors (461021367477).
1351113005643 is a wasteful number, since it uses less digits than its factorization.
1351113005643 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4187.
The product of its (nonzero) digits is 16200, while the sum is 33.
The spelling of 1351113005643 in words is "one trillion, three hundred fifty-one billion, one hundred thirteen million, five thousand, six hundred forty-three".
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