Base | Representation |
---|---|
bin | 10011101010010101000… |
… | …011001000001111110111 |
3 | 11210011110220022121211101 |
4 | 103222111003020033313 |
5 | 134114043302400333 |
6 | 2512410210150531 |
7 | 166421010352222 |
oct | 23522503101767 |
9 | 4704426277741 |
10 | 1351120356343 |
11 | 48100924357a |
12 | 199a33582447 |
13 | 9a543cc44c4 |
14 | 495749d65b9 |
15 | 2522bd2267d |
hex | 13a950c83f7 |
1351120356343 has 4 divisors (see below), whose sum is σ = 1351127434320. Its totient is φ = 1351113278368.
The previous prime is 1351120356317. The next prime is 1351120356347. The reversal of 1351120356343 is 3436530211531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1351120356343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1351120356347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3244483 + ... + 3637156.
It is an arithmetic number, because the mean of its divisors is an integer number (337781858580).
Almost surely, 21351120356343 is an apocalyptic number.
1351120356343 is a deficient number, since it is larger than the sum of its proper divisors (7077977).
1351120356343 is an equidigital number, since it uses as much as digits as its factorization.
1351120356343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7077976.
The product of its (nonzero) digits is 97200, while the sum is 37.
Adding to 1351120356343 its reverse (3436530211531), we get a palindrome (4787650567874).
The spelling of 1351120356343 in words is "one trillion, three hundred fifty-one billion, one hundred twenty million, three hundred fifty-six thousand, three hundred forty-three".
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