Search a number
-
+
1351120356343 = 1963376881639
BaseRepresentation
bin10011101010010101000…
…011001000001111110111
311210011110220022121211101
4103222111003020033313
5134114043302400333
62512410210150531
7166421010352222
oct23522503101767
94704426277741
101351120356343
1148100924357a
12199a33582447
139a543cc44c4
14495749d65b9
152522bd2267d
hex13a950c83f7

1351120356343 has 4 divisors (see below), whose sum is σ = 1351127434320. Its totient is φ = 1351113278368.

The previous prime is 1351120356317. The next prime is 1351120356347. The reversal of 1351120356343 is 3436530211531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1351120356343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1351120356347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3244483 + ... + 3637156.

It is an arithmetic number, because the mean of its divisors is an integer number (337781858580).

Almost surely, 21351120356343 is an apocalyptic number.

1351120356343 is a deficient number, since it is larger than the sum of its proper divisors (7077977).

1351120356343 is an equidigital number, since it uses as much as digits as its factorization.

1351120356343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7077976.

The product of its (nonzero) digits is 97200, while the sum is 37.

Adding to 1351120356343 its reverse (3436530211531), we get a palindrome (4787650567874).

The spelling of 1351120356343 in words is "one trillion, three hundred fifty-one billion, one hundred twenty million, three hundred fifty-six thousand, three hundred forty-three".

Divisors: 1 196337 6881639 1351120356343