Base | Representation |
---|---|
bin | 10011101010010101000… |
… | …011001000001111111011 |
3 | 11210011110220022121211112 |
4 | 103222111003020033323 |
5 | 134114043302400342 |
6 | 2512410210150535 |
7 | 166421010352226 |
oct | 23522503101773 |
9 | 4704426277745 |
10 | 1351120356347 |
11 | 481009243583 |
12 | 199a3358244b |
13 | 9a543cc44c8 |
14 | 495749d65bd |
15 | 2522bd22682 |
hex | 13a950c83fb |
1351120356347 has 2 divisors, whose sum is σ = 1351120356348. Its totient is φ = 1351120356346.
The previous prime is 1351120356317. The next prime is 1351120356367. The reversal of 1351120356347 is 7436530211531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1351120356347 - 210 = 1351120355323 is a prime.
It is not a weakly prime, because it can be changed into another prime (1351120356317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675560178173 + 675560178174.
It is an arithmetic number, because the mean of its divisors is an integer number (675560178174).
Almost surely, 21351120356347 is an apocalyptic number.
1351120356347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351120356347 is an equidigital number, since it uses as much as digits as its factorization.
1351120356347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 226800, while the sum is 41.
Adding to 1351120356347 its reverse (7436530211531), we get a palindrome (8787650567878).
The spelling of 1351120356347 in words is "one trillion, three hundred fifty-one billion, one hundred twenty million, three hundred fifty-six thousand, three hundred forty-seven".
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