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1351120455073 is a prime number
BaseRepresentation
bin10011101010010101000…
…011100000010110100001
311210011110220111122021001
4103222111003200112201
5134114043314030243
62512410212232001
7166421011243114
oct23522503402641
94704426448231
101351120455073
11481009300774
12199a3360b601
139a54402a41c
1449574a2057b
152522bd41a4d
hex13a950e05a1

1351120455073 has 2 divisors, whose sum is σ = 1351120455074. Its totient is φ = 1351120455072.

The previous prime is 1351120455031. The next prime is 1351120455133. The reversal of 1351120455073 is 3705540211531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1345767045184 + 5353409889 = 1160072^2 + 73167^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351120455073 - 29 = 1351120454561 is a prime.

It is a super-2 number, since 2×13511204550732 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1351120450073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675560227536 + 675560227537.

It is an arithmetic number, because the mean of its divisors is an integer number (675560227537).

Almost surely, 21351120455073 is an apocalyptic number.

It is an amenable number.

1351120455073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351120455073 is an equidigital number, since it uses as much as digits as its factorization.

1351120455073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63000, while the sum is 37.

The spelling of 1351120455073 in words is "one trillion, three hundred fifty-one billion, one hundred twenty million, four hundred fifty-five thousand, seventy-three".