Base | Representation |
---|---|
bin | 11001001010101011… |
… | …00100101100011011 |
3 | 1021212121220212200120 |
4 | 30211111210230123 |
5 | 210132344023303 |
6 | 10112414204323 |
7 | 655552163412 |
oct | 144525445433 |
9 | 37777825616 |
10 | 13511314203 |
11 | 580386a382 |
12 | 2750ab36a3 |
13 | 13742b889a |
14 | 922628479 |
15 | 5412a2553 |
hex | 325564b1b |
13511314203 has 16 divisors (see below), whose sum is σ = 18214071456. Its totient is φ = 8908185600.
The previous prime is 13511314171. The next prime is 13511314207. The reversal of 13511314203 is 30241311531.
13511314203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13511314203 - 25 = 13511314171 is a prime.
It is a super-2 number, since 2×135113142032 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13511314207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 400803 + ... + 433203.
It is an arithmetic number, because the mean of its divisors is an integer number (1138379466).
Almost surely, 213511314203 is an apocalyptic number.
13511314203 is a deficient number, since it is larger than the sum of its proper divisors (4702757253).
13511314203 is a wasteful number, since it uses less digits than its factorization.
13511314203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33934.
The product of its (nonzero) digits is 1080, while the sum is 24.
Adding to 13511314203 its reverse (30241311531), we get a palindrome (43752625734).
The spelling of 13511314203 in words is "thirteen billion, five hundred eleven million, three hundred fourteen thousand, two hundred three".
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