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1351164202673 is a prime number
BaseRepresentation
bin10011101010010111101…
…010011000111010110001
311210011120221211020200112
4103222113222120322301
5134114141013441143
62512414414031105
7166422052140125
oct23522752307261
94704527736615
101351164202673
11481030a70a0a
12199a461a8495
139a55010698c
144957a76b585
1525230ad3e18
hex13a97a98eb1

1351164202673 has 2 divisors, whose sum is σ = 1351164202674. Its totient is φ = 1351164202672.

The previous prime is 1351164202667. The next prime is 1351164202681. The reversal of 1351164202673 is 3762024611531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 805770136609 + 545394066064 = 897647^2 + 738508^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351164202673 - 214 = 1351164186289 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1351164202673.

It is not a weakly prime, because it can be changed into another prime (1351164205673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675582101336 + 675582101337.

It is an arithmetic number, because the mean of its divisors is an integer number (675582101337).

Almost surely, 21351164202673 is an apocalyptic number.

It is an amenable number.

1351164202673 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351164202673 is an equidigital number, since it uses as much as digits as its factorization.

1351164202673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 41.

The spelling of 1351164202673 in words is "one trillion, three hundred fifty-one billion, one hundred sixty-four million, two hundred two thousand, six hundred seventy-three".