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13512013142 = 26756006571
BaseRepresentation
bin11001001010110000…
…01111010101010110
31021212200020101110012
430211120033111112
5210133033410032
610112441200222
7655561134215
oct144530172526
937780211405
1013512013142
1158041a7511
122751190072
1313744a1a64
1492276b07c
1554138e6b2
hex32560f556

13512013142 has 4 divisors (see below), whose sum is σ = 20268019716. Its totient is φ = 6756006570.

The previous prime is 13512013133. The next prime is 13512013157. The reversal of 13512013142 is 24131021531.

13512013142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3378003284 + ... + 3378003287.

It is an arithmetic number, because the mean of its divisors is an integer number (5067004929).

Almost surely, 213512013142 is an apocalyptic number.

13512013142 is a deficient number, since it is larger than the sum of its proper divisors (6756006574).

13512013142 is an equidigital number, since it uses as much as digits as its factorization.

13512013142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6756006573.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 13512013142 its reverse (24131021531), we get a palindrome (37643034673).

The spelling of 13512013142 in words is "thirteen billion, five hundred twelve million, thirteen thousand, one hundred forty-two".

Divisors: 1 2 6756006571 13512013142