13512113 has 2 divisors, whose sum is σ = 13512114. Its totient is φ = 13512112.

The previous prime is 13512073. The next prime is 13512131. The reversal of 13512113 is 31121531.

Together with next prime (13512131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11751184 + 1760929 = 3428^2 + 1327^2 .

It is a cyclic number.

It is not a de Polignac number, because 13512113 - 2¹² = 13508017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13512091 and 13512100.

It is not a weakly prime, because it can be changed into another prime (13512143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756056 + 6756057.

It is an arithmetic number, because the mean of its divisors is an integer number (6756057).

Almost surely, 2^13512113 is an apocalyptic number.

It is an amenable number.

13512113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13512113 is an equidigital number, since it uses as much as digits as its factorization.

13512113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 90, while the sum is 17.

The square root of 13512113 is about 3675.8826151008. The cubic root of 13512113 is about 238.1813520208.

Adding to 13512113 its reverse (31121531), we get a palindrome (44633644).

The spelling of 13512113 in words is "thirteen million, five hundred twelve thousand, one hundred thirteen".