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135121525303 = 751717975459
BaseRepresentation
bin111110111010111011…
…1101101101000110111
3110220202211222200120011
41331311313231220313
54203212102302203
6142023551121051
712522303005002
oct1756567555067
9426684880504
10135121525303
115233963a976
122222bb13187
13c984c7268b
14677b762539
1537ac7c276d
hex1f75deda37

135121525303 has 4 divisors (see below), whose sum is σ = 135139508280. Its totient is φ = 135103542328.

The previous prime is 135121525283. The next prime is 135121525333. The reversal of 135121525303 is 303525121531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135121525303 - 25 = 135121525271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135121525333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8980213 + ... + 8995246.

It is an arithmetic number, because the mean of its divisors is an integer number (33784877070).

Almost surely, 2135121525303 is an apocalyptic number.

135121525303 is a deficient number, since it is larger than the sum of its proper divisors (17982977).

135121525303 is an equidigital number, since it uses as much as digits as its factorization.

135121525303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17982976.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 135121525303 its reverse (303525121531), we get a palindrome (438646646834).

The spelling of 135121525303 in words is "one hundred thirty-five billion, one hundred twenty-one million, five hundred twenty-five thousand, three hundred three".

Divisors: 1 7517 17975459 135121525303