Base | Representation |
---|---|
bin | 111110111010111011… |
… | …1101101101000010111 |
3 | 110220202211222200111222 |
4 | 1331311313231220113 |
5 | 4203212102302041 |
6 | 142023551120555 |
7 | 12522303004625 |
oct | 1756567555027 |
9 | 426684880458 |
10 | 135121525271 |
11 | 5233963a947 |
12 | 2222bb1315b |
13 | c984c72665 |
14 | 677b762515 |
15 | 37ac7c274b |
hex | 1f75deda17 |
135121525271 has 2 divisors, whose sum is σ = 135121525272. Its totient is φ = 135121525270.
The previous prime is 135121525223. The next prime is 135121525283. The reversal of 135121525271 is 172525121531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135121525271 is a prime.
It is a super-2 number, since 2×1351215252712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135121525211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67560762635 + 67560762636.
It is an arithmetic number, because the mean of its divisors is an integer number (67560762636).
Almost surely, 2135121525271 is an apocalyptic number.
135121525271 is a deficient number, since it is larger than the sum of its proper divisors (1).
135121525271 is an equidigital number, since it uses as much as digits as its factorization.
135121525271 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21000, while the sum is 35.
The spelling of 135121525271 in words is "one hundred thirty-five billion, one hundred twenty-one million, five hundred twenty-five thousand, two hundred seventy-one".
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