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135131103000 = 23325373892311
BaseRepresentation
bin111110111011001110…
…0001111111100011000
3110220210112000021200200
41331312130033330120
54203222030244000
6142024532302200
712522450265215
oct1756634177430
9426715007620
10135131103000
1152343a91823
1222233171960
13c986c46c5a
14677cb36b0c
1537ad565500
hex1f7670ff18

135131103000 has 384 divisors, whose sum is σ = 468404726400. Its totient is φ = 35126784000.

The previous prime is 135131102993. The next prime is 135131103007. The reversal of 135131103000 is 301131531.

135131103000 is a `hidden beast` number, since 1 + 3 + 51 + 311 + 0 + 300 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (135131102993) and next prime (135131103007).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135131103007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 58471845 + ... + 58474155.

It is an arithmetic number, because the mean of its divisors is an integer number (1219803975).

Almost surely, 2135131103000 is an apocalyptic number.

135131103000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135131103000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (234202363200).

135131103000 is an abundant number, since it is smaller than the sum of its proper divisors (333273623400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135131103000 is a wasteful number, since it uses less digits than its factorization.

135131103000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2500 (or 2483 counting only the distinct ones).

The product of its (nonzero) digits is 135, while the sum is 18.

Adding to 135131103000 its reverse (301131531), we get a palindrome (135432234531).

The spelling of 135131103000 in words is "one hundred thirty-five billion, one hundred thirty-one million, one hundred three thousand".