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135133000533000 = 233253461213715241
BaseRepresentation
bin11110101110011100011010…
…011111101000010000001000
3122201110120220011002112021200
4132232130122133220100020
5120203004341114024000
61155223124325304200
740315015504303611
oct3656343237502010
9581416804075250
10135133000533000
113a06a646988758
12131a5820565060
135a52cab060c92
142552687714c08
1510951bd27a500
hex7ae71a7e8408

135133000533000 has 384 divisors, whose sum is σ = 457984566879840. Its totient is φ = 35938114560000.

The previous prime is 135133000532921. The next prime is 135133000533017. The reversal of 135133000533000 is 335000331531.

It is a happy number.

135133000533000 is a `hidden beast` number, since 1 + 3 + 5 + 1 + 3 + 300 + 0 + 53 + 300 + 0 = 666.

135133000533000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 16 ways, for example, as 23942682051876 + 111190318481124 = 4893126^2 + 10544682^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 8866405380 + ... + 8866420620.

Almost surely, 2135133000533000 is an apocalyptic number.

135133000533000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135133000533000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (228992283439920).

135133000533000 is an abundant number, since it is smaller than the sum of its proper divisors (322851566346840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135133000533000 is a wasteful number, since it uses less digits than its factorization.

135133000533000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17866 (or 17849 counting only the distinct ones).

The product of its (nonzero) digits is 6075, while the sum is 27.

Adding to 135133000533000 its reverse (335000331531), we get a palindrome (135468000864531).

The spelling of 135133000533000 in words is "one hundred thirty-five trillion, one hundred thirty-three billion, five hundred thirty-three thousand".