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13513541524051 is a prime number
BaseRepresentation
bin1100010010100101110111…
…0101111001101001010011
31202211212210221110221022211
43010221131311321221103
53232401213112232201
644424011341412551
72563215104466022
oct304513565715123
952755727427284
1013513541524051
114340073990688
12162302186a157
1377042443b3ca
1434a0b78988b9
151867b9038651
hexc4a5dd79a53

13513541524051 has 2 divisors, whose sum is σ = 13513541524052. Its totient is φ = 13513541524050.

The previous prime is 13513541524003. The next prime is 13513541524193. The reversal of 13513541524051 is 15042514531531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13513541524051 - 235 = 13479181785683 is a prime.

It is a super-2 number, since 2×135135415240512 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13513541523995 and 13513541524013.

It is not a weakly prime, because it can be changed into another prime (13513541524451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756770762025 + 6756770762026.

It is an arithmetic number, because the mean of its divisors is an integer number (6756770762026).

Almost surely, 213513541524051 is an apocalyptic number.

13513541524051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13513541524051 is an equidigital number, since it uses as much as digits as its factorization.

13513541524051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 40.

The spelling of 13513541524051 in words is "thirteen trillion, five hundred thirteen billion, five hundred forty-one million, five hundred twenty-four thousand, fifty-one".