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135136316143400 = 2352111313734489387
BaseRepresentation
bin11110101110011111100000…
…000111101011011100101000
3122201110220110012222222200212
4132232133200013223130220
5120203033133413042100
61155224433330320252
740315163614443335
oct3656374007533450
9581426405888625
10135136316143400
113a070a98514940
12131a63a6a29088
135a533b8c4a720
1425528bdbd598c
1510953143b3635
hex7ae7e01eb728

135136316143400 has 192 divisors, whose sum is σ = 371814916697280. Its totient is φ = 45029342361600.

The previous prime is 135136316143399. The next prime is 135136316143469. The reversal of 135136316143400 is 4341613631531.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 13326494 + ... + 21162893.

It is an arithmetic number, because the mean of its divisors is an integer number (1936536024465).

Almost surely, 2135136316143400 is an apocalyptic number.

135136316143400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

135136316143400 is an abundant number, since it is smaller than the sum of its proper divisors (236678600553880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135136316143400 is a wasteful number, since it uses less digits than its factorization.

135136316143400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34489564 (or 34489555 counting only the distinct ones).

The product of its (nonzero) digits is 233280, while the sum is 41.

Adding to 135136316143400 its reverse (4341613631531), we get a palindrome (139477929774931).

The spelling of 135136316143400 in words is "one hundred thirty-five trillion, one hundred thirty-six billion, three hundred sixteen million, one hundred forty-three thousand, four hundred".