Base | Representation |
---|---|
bin | 111110111011110100… |
… | …0111011100110010001 |
3 | 110220211220211120010001 |
4 | 1331313220323212101 |
5 | 4203242202023003 |
6 | 142030531210001 |
7 | 12523113200005 |
oct | 1756750734621 |
9 | 426756746101 |
10 | 135151204753 |
11 | 52354371544 |
12 | 22239a46901 |
13 | c98b164796 |
14 | 678168a705 |
15 | 37b01d661d |
hex | 1f77a3b991 |
135151204753 has 2 divisors, whose sum is σ = 135151204754. Its totient is φ = 135151204752.
The previous prime is 135151204687. The next prime is 135151204763. The reversal of 135151204753 is 357402151531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 73868716944 + 61282487809 = 271788^2 + 247553^2 .
It is a cyclic number.
It is not a de Polignac number, because 135151204753 - 29 = 135151204241 is a prime.
It is not a weakly prime, because it can be changed into another prime (135151204763) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67575602376 + 67575602377.
It is an arithmetic number, because the mean of its divisors is an integer number (67575602377).
Almost surely, 2135151204753 is an apocalyptic number.
It is an amenable number.
135151204753 is a deficient number, since it is larger than the sum of its proper divisors (1).
135151204753 is an equidigital number, since it uses as much as digits as its factorization.
135151204753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63000, while the sum is 37.
The spelling of 135151204753 in words is "one hundred thirty-five billion, one hundred fifty-one million, two hundred four thousand, seven hundred fifty-three".
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