Base | Representation |
---|---|
bin | 10011101010110011110… |
… | …111001111100101011001 |
3 | 11210012210221002211100101 |
4 | 103222303313033211121 |
5 | 134121123124144421 |
6 | 2512533354535401 |
7 | 166436555530606 |
oct | 23526367174531 |
9 | 4705727084311 |
10 | 1351637334361 |
11 | 481254046836 |
12 | 199b58737561 |
13 | 9a5c7142362 |
14 | 495c352b6ad |
15 | 2525c3e1191 |
hex | 13ab3dcf959 |
1351637334361 has 2 divisors, whose sum is σ = 1351637334362. Its totient is φ = 1351637334360.
The previous prime is 1351637334343. The next prime is 1351637334367. The reversal of 1351637334361 is 1634337361531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1169782849225 + 181854485136 = 1081565^2 + 426444^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351637334361 - 211 = 1351637332313 is a prime.
It is a super-2 number, since 2×13516373343612 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1351637334367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675818667180 + 675818667181.
It is an arithmetic number, because the mean of its divisors is an integer number (675818667181).
Almost surely, 21351637334361 is an apocalyptic number.
It is an amenable number.
1351637334361 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351637334361 is an equidigital number, since it uses as much as digits as its factorization.
1351637334361 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1224720, while the sum is 46.
The spelling of 1351637334361 in words is "one trillion, three hundred fifty-one billion, six hundred thirty-seven million, three hundred thirty-four thousand, three hundred sixty-one".
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