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135201134335 = 5209912882433
BaseRepresentation
bin111110111101010011…
…1011001011011111111
3110220222101210020121211
41331322213121123333
54203342442244320
6142035513305251
712524260452211
oct1757247313377
9426871706554
10135201134335
115237a574363
1222252705227
13c9985c6b07
1467881665b1
1537b479a55a
hex1f7a9d96ff

135201134335 has 8 divisors (see below), whose sum is σ = 162318668400. Its totient is φ = 108109369344.

The previous prime is 135201134273. The next prime is 135201134357. The reversal of 135201134335 is 533431102531.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135201134335 - 213 = 135201126143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135201134297 and 135201134306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6430722 + ... + 6451711.

It is an arithmetic number, because the mean of its divisors is an integer number (20289833550).

Almost surely, 2135201134335 is an apocalyptic number.

135201134335 is a deficient number, since it is larger than the sum of its proper divisors (27117534065).

135201134335 is a wasteful number, since it uses less digits than its factorization.

135201134335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12884537.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 135201134335 its reverse (533431102531), we get a palindrome (668632236866).

The spelling of 135201134335 in words is "one hundred thirty-five billion, two hundred one million, one hundred thirty-four thousand, three hundred thirty-five".

Divisors: 1 5 2099 10495 12882433 64412165 27040226867 135201134335