Base | Representation |
---|---|
bin | 11110101111011011111100… |
… | …010111011101110100011011 |
3 | 122201201002222002210210200121 |
4 | 132233123330113131310123 |
5 | 120210114041411201441 |
6 | 1155314325220414111 |
7 | 40322652064021561 |
oct | 3657337427356433 |
9 | 581632862723617 |
10 | 135201214553371 |
11 | 3a096570a218aa |
12 | 131b6a99247337 |
13 | 5a5955c487045 |
14 | 2555ab9063a31 |
15 | 1096d61ba1dd1 |
hex | 7af6fc5ddd1b |
135201214553371 has 2 divisors, whose sum is σ = 135201214553372. Its totient is φ = 135201214553370.
The previous prime is 135201214553299. The next prime is 135201214553389. The reversal of 135201214553371 is 173355412102531.
It is a strong prime.
It is an emirp because it is prime and its reverse (173355412102531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135201214553371 - 217 = 135201214422299 is a prime.
It is not a weakly prime, because it can be changed into another prime (135201214353371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67600607276685 + 67600607276686.
It is an arithmetic number, because the mean of its divisors is an integer number (67600607276686).
Almost surely, 2135201214553371 is an apocalyptic number.
135201214553371 is a deficient number, since it is larger than the sum of its proper divisors (1).
135201214553371 is an equidigital number, since it uses as much as digits as its factorization.
135201214553371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378000, while the sum is 43.
The spelling of 135201214553371 in words is "one hundred thirty-five trillion, two hundred one billion, two hundred fourteen million, five hundred fifty-three thousand, three hundred seventy-one".
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